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  <title>joshuazelinsky</title>
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  <lastBuildDate>Tue, 10 Mar 2020 13:08:42 GMT</lastBuildDate>
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  <pubDate>Tue, 10 Mar 2020 13:08:42 GMT</pubDate>
  <title>An Introduction to Integer Complexity</title>
  <link>https://joshuazelinsky.dreamwidth.org/2377.html</link>
  <description>&lt;font color=&quot;#1d2129&quot; face=&quot;Helvetica, Arial, sans-serif&quot;&gt;&lt;span style=&quot;font-size: 14px;&quot;&gt;(Note: I&apos;m in the process of copying some older math posts from Facebook over here with some slight modifications. This is one of those.)&lt;br /&gt;&lt;br /&gt; There are a lot of times people talk about famous open mathematical problems. But less attention is paid to some of the problems that are both simple to state and aren&apos;t very famous at all. Let&apos;s talk about one of those not so famous but still simple open problems.&lt;/span&gt;&lt;/font&gt;&lt;p style=&quot;margin: 6px 0px; font-family: Helvetica, Arial, sans-serif; color: rgb(29, 33, 41); font-size: 14px;&quot;&gt;We&apos;re interested in the minimum number of 1s needed to write a positive integer n as a product or sum of 1s, using any number of parentheses, and we&apos;ll call that ||n||. For example, the equation 6=(1+1)(1+1+1) shows that ||6|| is at most 5, since it took 5 1s. A little playing around will convince you that you cannot write 6 using just four or fewer 1s, so it is really is the case that ||6||=5. We call ||n|| the integer complexity of n.&lt;/p&gt;&lt;p style=&quot;margin: 6px 0px; font-family: Helvetica, Arial, sans-serif; color: rgb(29, 33, 41); font-size: 14px;&quot;&gt;Now here&apos;s the problem: Does every power of 2 have a most efficient representation the obvious way? That is, is it is always true f(2^k)= 2k? For example, 8=(1+1)(1+1)(1+1) and in fact ||8||=6. Similarly, 16 = (1+1)(1+1)(1+1)(1+1), and ||16||=8. (Note that we sometimes have representations which are tied for writing it this way; for example we can also write 8 = (1+1+1+1)(1+1) but that also takes 6 ones, not fewer).&lt;/p&gt;&lt;p style=&quot;margin: 6px 0px; font-family: Helvetica, Arial, sans-serif; color: rgb(29, 33, 41); font-size: 14px;&quot;&gt;One might think that the answer should be obviously yes, so let&apos;s look for a moment at powers of 5. Does every power of 5 have the obvious representation as best? We&apos;d expect from ||5||=5, to get that ||25||=10, and we do. The pattern continues with ||5^3||=15, and ||5^4||=20, and ||5^5||=25, but then it breaks down, ||5^6||=29. This in some sense happens because 5^6-1 has a lot of small prime factors. But it isn&apos;t obvious that something similar couldn&apos;t happen with powers of 2. This problem was as far as I&apos;m aware, first proposed by Richard Guy. This is a problem which is dear to me and one which I&apos;m responsible for some of the progress on with &lt;a href=&quot;https://sniffnoy.dreamwidth.org/&quot;&gt;Harry Altman&lt;/a&gt; who has written a lot about this problem on his Dreamwidth discussing his published works on the problem.&amp;nbsp;&lt;br /&gt;&amp;nbsp;&lt;/p&gt;&lt;p style=&quot;margin: 6px 0px 0px; display: inline; font-family: Helvetica, Arial, sans-serif; color: rgb(29, 33, 41); font-size: 14px;&quot;&gt;My intuition on this problem keeps jumping back and forth on whether it is true or not. Right now, I&apos;m leaning towards it being false.&lt;/p&gt;&lt;br /&gt;&lt;br /&gt;&lt;img src=&quot;https://www.dreamwidth.org/tools/commentcount?user=joshuazelinsky&amp;ditemid=2377&quot; width=&quot;30&quot; height=&quot;12&quot; alt=&quot;comment count unavailable&quot; style=&quot;vertical-align: middle;&quot;/&gt; comments</description>
  <comments>https://joshuazelinsky.dreamwidth.org/2377.html</comments>
  <category>math</category>
  <category>integer complexity</category>
  <category>number theory</category>
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  <lj:reply-count>0</lj:reply-count>
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